Difference between revisions of "2019 AMC 12A Problems/Problem 2"
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==Solution== | ==Solution== | ||
| − | <math>a=1.5b</math> | + | Since <math>a=1.5b</math>, that means <math>b=a/1.5</math>. We multiply by 3 to get a <math>3b</math> term, to yield <math>3b=2a</math>. |
| − | + | <math>2a</math> is <math>\boxed{200\%}</math> of <math>a</math>. | |
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| − | <math>2a</math> is <math>\boxed{200}</math> of <math>a</math>. | ||
==See Also== | ==See Also== | ||
Revision as of 17:12, 9 February 2019
Problem
Suppose 
is 
of 
. What percent of is 
?
Solution
Since 
, that means 
. We multiply by 3 to get a term, to yield 
.
is 
of .
See Also
| 2019 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
