Difference between revisions of "1981 AHSME Problems/Problem 3"
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The least common multiple of <math>\frac{1}{x}</math>, <math>\frac{1}{2x}</math>, and <math>\frac{1}{3x}</math> is <math>\frac{1}{6x}</math>. | The least common multiple of <math>\frac{1}{x}</math>, <math>\frac{1}{2x}</math>, and <math>\frac{1}{3x}</math> is <math>\frac{1}{6x}</math>. | ||
| − | <math>\frac{1}{x}</math>=<math>\frac{6}{6x}</math>, <math>\frac{1}{2x}</math>=<math>\frac{3}{6x}</math>, <math>\frac{1}{3x}</math>=<math>\frac{2}{6x}</math>. | + | <math>\frac{1}{x}</math> = <math>\frac{6}{6x}</math>, <math>\frac{1}{2x}</math> = <math>\frac{3}{6x}</math>, <math>\frac{1}{3x}</math> = <math>\frac{2}{6x}</math>. |
| − | <math>\frac{6}{6x}</math>+<math>\frac{3}{6x}</math>+<math>\frac{2}{6x}</math>=<math>\frac{11}{6x}</math> | + | <math>\frac{6}{6x}</math> + <math>\frac{3}{6x}</math> + <math>\frac{2}{6x}</math> = <math>\frac{11}{6x}</math> |
The answer is (D) <math>\frac{11}{6x}</math>. | The answer is (D) <math>\frac{11}{6x}</math>. | ||
Revision as of 10:59, 21 November 2018
Solution
The least common multiple of 
, 
, and 
is 
.
= 
, = 
, = 
.
+ + = 
The answer is (D) .
