Difference between revisions of "2018 AMC 10B Problems/Problem 1"

Revision as of 00:11, 9 January 2019

Problem

Kate bakes a $20$ -inch by $18$ -inch pan of cornbread. The cornbread is cut into pieces that measure $2$ inches by $2$ inches. How many pieces of cornbread does the pan contain?

$\textbf{(A) } 90 \qquad \textbf{(B) } 100 \qquad \textbf{(C) } 180 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 360$

Solution 1

The area of the pan is $20\cdot18$ = $360$ . Since the area of each piece is $4$ , there are $\frac{360}{4} = 90$ pieces. Thus, the answer is $\boxed{A}$ .

Solution 2

By dividing each of the dimensions by $2$ , we get a $10\times9$ grid which makes $90$ pieces. Thus, the answer is $\boxed{A}$ .

Solution 3

Hack into the system containing all the answers, and find the solution to problem which is $\boxed{A}$

2018 AMC 10B (Problems • Answer Key • Resources)
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All AMC 10 Problems and Solutions

2018 AMC 12B (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
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All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

@@ Line 11: / Line 11: @@
 By dividing each of the dimensions by <math>2</math>, we get a <math>10\times9</math> grid which makes <math>90</math> pieces. Thus, the answer is <math>\boxed{A}</math>.
+== Solution 3 ==
+Hack into the system containing all the answers, and find the solution to problem which is <math>\boxed{A}</math>
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