Difference between revisions of "1950 AHSME Problems/Problem 34"
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==Solution 2== | ==Solution 2== | ||
| − | The radii of the | + | The radii of the circles are <math>\frac{20}{2\pi}</math> and <math>\frac{25}{2\pi}</math>, respectively. The positive difference is therefore <math>\boxed{\textbf{(D)}\ \dfrac{5}{2\pi}\text{ in}}</math>. |
==See Also== | ==See Also== | ||
Revision as of 19:59, 20 March 2018
Contents
Problem
When the circumference of a toy balloon is increased from 
inches to 
inches, the radius is increased by:
Solution
When the circumference of a circle is increased by a percentage, the radius is also increased by the same percentage (or else the ratio of the circumference to the diameter wouldn't be 
anymore)
We see that the circumference was increased by 
. This means the radius was also increased by . The radius of the original balloon is 
. With the increase, it becomes 
. The increase is 
Solution 2
The radii of the circles are 
and 
, respectively. The positive difference is therefore 
.
See Also
| 1950 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 33 |
Followed by Problem 35 | |
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| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
