Difference between revisions of "1967 IMO Problems/Problem 3"

(Created page with "Let <math>k, m, n</math> be natural numbers such that <math>m+k+1</math> is a prime greater than <math>n+1.</math> Let <math>c_s=s(s+1).</math> Prove that the product <cmath>(...")
 
m
Line 1: Line 1:
 +
==Problem==
 
Let <math>k, m, n</math> be natural numbers such that <math>m+k+1</math> is a prime greater than <math>n+1.</math> Let <math>c_s=s(s+1).</math> Prove that the product <cmath>(c_{m+1}-c_k)(c_{m+2}-c_k)\cdots (c_{m+n}-c_k)</cmath> is divisible by the product <math>c_1c_2\cdots c_n</math>.
 
Let <math>k, m, n</math> be natural numbers such that <math>m+k+1</math> is a prime greater than <math>n+1.</math> Let <math>c_s=s(s+1).</math> Prove that the product <cmath>(c_{m+1}-c_k)(c_{m+2}-c_k)\cdots (c_{m+n}-c_k)</cmath> is divisible by the product <math>c_1c_2\cdots c_n</math>.
----
+
 
 +
==Solution==
 +
{{solution}}
 +
 
 +
==See Also==
 +
 
 +
{{IMO box|year=1967|num-b=1|num-a=3}}
 +
[[Category:Olympiad Geometry Problems]]

Revision as of 13:53, 17 February 2018

Problem

Let $k, m, n$ be natural numbers such that $m+k+1$ is a prime greater than $n+1.$ Let $c_s=s(s+1).$ Prove that the product \[(c_{m+1}-c_k)(c_{m+2}-c_k)\cdots (c_{m+n}-c_k)\] is divisible by the product $c_1c_2\cdots c_n$.

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See Also

1967 IMO (Problems) • Resources
Preceded by
Problem 1
1 2 3 4 5 6 Followed by
Problem 3
All IMO Problems and Solutions