Difference between revisions of "2005 Canadian MO Problems/Problem 2"

Revision as of 19:32, 28 July 2006

Let $(a,b,c)$ be a Pythagorean triple, i.e., a triplet of positive integers with ${a}^2+{b}^2={c}^2$ .

Prove that $(c/a + c/b)^2 > 8$ .
Prove that there does not exist any integer $n$ for which we can find a Pythagorean triple $(a,b,c)$ satisfying $(c/a + c/b)^2 = n$ .

Revision as of 17:52, 28 July 2006 (view source) Chess64 (talk \| contribs) ← Older edit	Revision as of 19:32, 28 July 2006 (view source) Chess64 (talk \| contribs) m (2005 Canadian MO/Problem 2 moved to 2005 Canadian MO Problems/Problem 2) Newer edit →
(No difference)