Difference between revisions of "2007 AMC 10A Problems/Problem 3"
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== Solution == | == Solution == | ||
| − | + | The volume of the brick is <math>40 \times 20 \times 10 = 8000</math>. Thus the water volume rose <math>8000 = 100 \times 40 \times h \Longrightarrow h = 2\ \mathrm{(D)}</math>. | |
== See also == | == See also == | ||
Latest revision as of 02:48, 19 June 2017
Problem
An aquarium has a rectangular base that measures 
cm by 
cm and has a height of 
cm. It is filled with water to a height of cm. A brick with a rectangular base that measures cm by 
cm and a height of 
cm is placed in the aquarium. By how many centimeters does the water rise?
Solution
The volume of the brick is 
. Thus the water volume rose 
.
See also
| 2007 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
