Difference between revisions of "2011 AMC 10A Problems/Problem 15"
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== Solution 2 : Using the Answer Choices== | == Solution 2 : Using the Answer Choices== | ||
| − | + | We know that the answer has to be divisible by <math>55</math>, and thus, the only answer that is divisible by 55 is <math>\boxed{440 \ \mathbf{(C)}}</math>. | |
== See Also == | == See Also == | ||
{{AMC10 box|year=2011|ab=A|num-b=14|num-a=16}} | {{AMC10 box|year=2011|ab=A|num-b=14|num-a=16}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 16:56, 30 December 2017
Problem 15
Roy bought a new battery-gasoline hybrid car. On a trip the car ran exclusively on its battery for the first 
miles, then ran exclusively on gasoline for the rest of the trip, using gasoline at a rate of 
gallons per mile. On the whole trip he averaged 
miles per gallon. How long was the trip in miles?
Solution 1
We know that 
. Let 
be the distance the car traveled during the time it ran on gasoline, then the amount of gas used is 
. The total distance traveled is 
, so we get 
. Solving this equation, we get 
, so the total distance is 
.
Solution 2 : Using the Answer Choices
We know that the answer has to be divisible by , and thus, the only answer that is divisible by 55 is 
.
See Also
| 2011 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 14 |
Followed by Problem 16 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
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