Difference between revisions of "2016 AMC 8 Problems/Problem 6"
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The following bar graph represents the length (in letters) of the names of 19 people. What is the median length of these names? | The following bar graph represents the length (in letters) of the names of 19 people. What is the median length of these names? | ||
<math>\textbf{(A) }3\qquad\textbf{(B) }4\qquad\textbf{(C) }5\qquad\textbf{(D) }6\qquad \textbf{(E) }7</math> | <math>\textbf{(A) }3\qquad\textbf{(B) }4\qquad\textbf{(C) }5\qquad\textbf{(D) }6\qquad \textbf{(E) }7</math> | ||
− | [ | + | [asy] |
+ | unitsize(0.9cm); | ||
+ | draw((-0.5,0)--(10,0), linewidth(1.5)); | ||
+ | draw((-0.5,1)--(10,1)); | ||
+ | draw((-0.5,2)--(10,2)); | ||
+ | draw((-0.5,3)--(10,3)); | ||
+ | draw((-0.5,4)--(10,4)); | ||
+ | draw((-0.5,5)--(10,5)); | ||
+ | draw((-0.5,6)--(10,6)); | ||
+ | draw((-0.5,7)--(10,7)); | ||
+ | label("frequency",(-0.5,8)); | ||
+ | label("0", (-1, 0)); | ||
+ | label("1", (-1, 1)); | ||
+ | label("2", (-1, 2)); | ||
+ | label("3", (-1, 3)); | ||
+ | label("4", (-1, 4)); | ||
+ | label("5", (-1, 5)); | ||
+ | label("6", (-1, 6)); | ||
+ | label("7", (-1, 7)); | ||
+ | filldraw((0,0)--(0,7)--(1,7)--(1,0)--cycle, black); | ||
+ | filldraw((2,0)--(2,3)--(3,3)--(3,0)--cycle, black); | ||
+ | filldraw((4,0)--(4,1)--(5,1)--(5,0)--cycle, black); | ||
+ | filldraw((6,0)--(6,4)--(7,4)--(7,0)--cycle, black); | ||
+ | filldraw((8,0)--(8,4)--(9,4)--(9,0)--cycle, black); | ||
+ | label("3", (0.5, -0.5)); | ||
+ | label("4", (2.5, -0.5)); | ||
+ | label("5", (4.5, -0.5)); | ||
+ | label("6", (6.5, -0.5)); | ||
+ | label("7", (8.5, -0.5)); | ||
+ | [/asy] | ||
==Solution== | ==Solution== |
Revision as of 14:28, 23 November 2016
The following bar graph represents the length (in letters) of the names of 19 people. What is the median length of these names? [asy] unitsize(0.9cm); draw((-0.5,0)--(10,0), linewidth(1.5)); draw((-0.5,1)--(10,1)); draw((-0.5,2)--(10,2)); draw((-0.5,3)--(10,3)); draw((-0.5,4)--(10,4)); draw((-0.5,5)--(10,5)); draw((-0.5,6)--(10,6)); draw((-0.5,7)--(10,7)); label("frequency",(-0.5,8)); label("0", (-1, 0)); label("1", (-1, 1)); label("2", (-1, 2)); label("3", (-1, 3)); label("4", (-1, 4)); label("5", (-1, 5)); label("6", (-1, 6)); label("7", (-1, 7)); filldraw((0,0)--(0,7)--(1,7)--(1,0)--cycle, black); filldraw((2,0)--(2,3)--(3,3)--(3,0)--cycle, black); filldraw((4,0)--(4,1)--(5,1)--(5,0)--cycle, black); filldraw((6,0)--(6,4)--(7,4)--(7,0)--cycle, black); filldraw((8,0)--(8,4)--(9,4)--(9,0)--cycle, black); label("3", (0.5, -0.5)); label("4", (2.5, -0.5)); label("5", (4.5, -0.5)); label("6", (6.5, -0.5)); label("7", (8.5, -0.5)); [/asy]
Solution
We first notice that the median name will be the name. We take all the letter names away from the list to see that the name in the new table is the desired length. Since there are names that are letters long, the median name length is .
2016 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |