Difference between revisions of "2016 AMC 8 Problems/Problem 6"
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==Solution== | ==Solution== | ||
| − | We first notice that the median name will be the <math>10-</math>th name. We subtract all the <math>3 | + | We first notice that the median name will be the <math>10-</math>th name. We subtract all the <math>3</math> letter names from the list to see that the <math>3</math>rd name in the new table is the desired length. Since there are <math>3</math> names that are <math>4</math> letters long, the median name length is <math>(B) 4</math>. |
{{AMC8 box|year=2016|num-b=5|num-a=7}} | {{AMC8 box|year=2016|num-b=5|num-a=7}} | ||
Revision as of 12:12, 23 November 2016
The following bar graph represents the length (in letters) of the names of 19 people. What is the median length of these names?
Solution
We first notice that the median name will be the 
th name. We subtract all the 
letter names from the list to see that the rd name in the new table is the desired length. Since there are names that are 
letters long, the median name length is 
.
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
