Difference between revisions of "2016 AMC 8 Problems/Problem 1"
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| − | We know that there is <math>60</math> minutes in a hour. | + | It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes. We know that there is <math>60</math> minutes in a hour. Therefore, there are <math>11 \cdot 60 = 600 + 60 = 660</math> minutes in 11 hours. Adding the second part, we get <math>660 + 5 = \boxed{665}</math>. |
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{{AMC8 box|year=2016|before=First Problem|num-a=2}} | {{AMC8 box|year=2016|before=First Problem|num-a=2}} | ||
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Revision as of 13:42, 23 November 2016
The longest professional tennis match ever played lasted a total of 
hours and 
minutes. How many minutes was this?
Solution
It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes. We know that there is 
minutes in a hour. Therefore, there are 
minutes in 11 hours. Adding the second part, we get 
.
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
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| All AJHSME/AMC 8 Problems and Solutions | ||
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