Difference between revisions of "1954 AHSME Problems/Problem 18"

(Created page with "== Problem 18== Of the following sets, the one that includes all values of <math>x</math> which will satisfy <math>2x - 3 > 7 - x</math> is: <math>\textbf{(A)}\ x > 4 \qqua...")
 
 
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== Solution ==
 
== Solution ==
 
<math>2x-3>7-x\implies 3x>10\implies \boxed{x>\frac{10}{3} (\textbf{D})}</math>.
 
<math>2x-3>7-x\implies 3x>10\implies \boxed{x>\frac{10}{3} (\textbf{D})}</math>.
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==See Also==
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{{AHSME 50p box|year=1954|num-b=17|num-a=19}}
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{{MAA Notice}}

Latest revision as of 00:28, 28 February 2020

Problem 18

Of the following sets, the one that includes all values of $x$ which will satisfy $2x - 3 > 7 - x$ is:

$\textbf{(A)}\ x > 4 \qquad \textbf{(B)}\ x < \frac {10}{3} \qquad \textbf{(C)}\ x = \frac {10}{3} \qquad \textbf{(D)}\ x >\frac{10}{3}\qquad\textbf{(E)}\ x < 0$

Solution

$2x-3>7-x\implies 3x>10\implies \boxed{x>\frac{10}{3} (\textbf{D})}$.

See Also

1954 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 17
Followed by
Problem 19
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All AHSME Problems and Solutions


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