Difference between revisions of "Ball-and-urn"

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m (n is the number of bins, and k is the number of objects. For the second case, k >= n so it must be k - 1 choose n -1)
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The '''ball-and-urn''' technique, also known as '''stars-and-bars''', is a commonly used technique in [[combinatorics]].
 
The '''ball-and-urn''' technique, also known as '''stars-and-bars''', is a commonly used technique in [[combinatorics]].
  
It is used to solve problems of the form: how many ways can one distribute <math>k</math> indistinguishable objects into <math>n</math> bins? We can imagine this as finding the number of ways to drop <math>k</math> balls into <math>n</math> urns, or equivalently to drop <math>k</math> balls amongst <math>n-1</math> dividers. The number of ways to do such is <math>{n+k-1 \choose k}</math>, given there can be <math>0</math> balls in an urn. However, if there can only be a positive amount of balls in an urn, then the number of ways to do such is <math>{n-1 \choose k-1}</math>
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It is used to solve problems of the form: how many ways can one distribute <math>k</math> indistinguishable objects into <math>n</math> bins? We can imagine this as finding the number of ways to drop <math>k</math> balls into <math>n</math> urns, or equivalently to drop <math>k</math> balls amongst <math>n-1</math> dividers. The number of ways to do such is <math>{n+k-1 \choose k}</math>, given there can be <math>0</math> balls in an urn. However, if there can only be a positive amount of balls in an urn, then the number of ways to do such is <math>{k-1 \choose n-1}</math>

Revision as of 01:45, 30 November 2016

The ball-and-urn technique, also known as stars-and-bars, is a commonly used technique in combinatorics.

It is used to solve problems of the form: how many ways can one distribute $k$ indistinguishable objects into $n$ bins? We can imagine this as finding the number of ways to drop $k$ balls into $n$ urns, or equivalently to drop $k$ balls amongst $n-1$ dividers. The number of ways to do such is ${n+k-1 \choose k}$, given there can be $0$ balls in an urn. However, if there can only be a positive amount of balls in an urn, then the number of ways to do such is ${k-1 \choose n-1}$