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Difference between revisions of "1956 AHSME Problems/Problem 1"

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== Solution ==
 
== Solution ==
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Simple substitution yields
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<cmath>2 + 2(2^2) = 2 + 2(4) = 10</cmath>
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Therefore, the answer is <math>\fbox{(A) 10}</math>

Revision as of 23:36, 30 December 2015

1956 AHSME Problem #1

The value of $x + x(x^x)$ when $x = 2$ is:

$\textbf{(A)}\ 10 \qquad\textbf{(B)}\ 16 \qquad\textbf{(C)}\ 18 \qquad\textbf{(D)}\ 36 \qquad\textbf{(E)}\ 64$

Solution

Simple substitution yields \[2 + 2(2^2) = 2 + 2(4) = 10\]

Therefore, the answer is $\fbox{(A) 10}$

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