Difference between revisions of "1987 AHSME Problems/Problem 30"
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In the figure, <math>\triangle ABC</math> has <math>\angle A =45^{\circ}</math> and <math>\angle B =30^{\circ}</math>. A line <math>DE</math>, with <math>D</math> on <math>AB</math> | In the figure, <math>\triangle ABC</math> has <math>\angle A =45^{\circ}</math> and <math>\angle B =30^{\circ}</math>. A line <math>DE</math>, with <math>D</math> on <math>AB</math> | ||
and <math>\angle ADE =60^{\circ}</math>, divides <math>\triangle ABC</math> into two pieces of equal area. | and <math>\angle ADE =60^{\circ}</math>, divides <math>\triangle ABC</math> into two pieces of equal area. | ||
− | (Note: the figure may not be accurate; perhaps <math>E</math> is on <math>CB</math> instead of <math>AC</math> | + | (Note: the figure may not be accurate; perhaps <math>E</math> is on <math>CB</math> instead of <math>AC.) </math> |
The ratio <math>\frac{AD}{AB}</math> is | The ratio <math>\frac{AD}{AB}</math> is | ||
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\textbf{(D)}\ \frac{1}{\sqrt[3]{6}}\qquad | \textbf{(D)}\ \frac{1}{\sqrt[3]{6}}\qquad | ||
\textbf{(E)}\ \frac{1}{\sqrt[4]{12}} </math> | \textbf{(E)}\ \frac{1}{\sqrt[4]{12}} </math> | ||
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== See also == | == See also == |
Revision as of 07:56, 23 October 2014
Problem
In the figure, has and . A line , with on and , divides into two pieces of equal area. (Note: the figure may not be accurate; perhaps is on instead of The ratio is
See also
1987 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 29 |
Followed by Last Question | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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