Difference between revisions of "1969 AHSME Problems/Problem 18"

(Created page with "== Problem == The number of points common to the graphs of <math>(x-y+2)(3x+y-4)=0 \text{ and } (x+y-2)(2x-5y+7)=0</math> is: <math>\text{(A) } 2\quad \text{(B) } 4\quad ...")
 
m (See also)
Line 16: Line 16:
 
{{AHSME 35p box|year=1969|num-b=17|num-a=19}}   
 
{{AHSME 35p box|year=1969|num-b=17|num-a=19}}   
  
[[Category: Introductory Geometry Problems]]
+
[[Category: Introductory Algebra Problems]]
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 16:48, 1 October 2014

Problem

The number of points common to the graphs of $(x-y+2)(3x+y-4)=0 \text{    and     } (x+y-2)(2x-5y+7)=0$ is:

$\text{(A) } 2\quad \text{(B) } 4\quad \text{(C) } 6\quad \text{(D) } 16\quad \text{(E) } \infty$

Solution

$\fbox{B}$

See also

1969 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 17
Followed by
Problem 19
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png