Difference between revisions of "1992 AHSME Problems/Problem 3"

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== Solution ==
 
== Solution ==
<math>\fbox{C}</math>
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We know that the formula for slope is <math>m = \frac{y_2-y_1}{x_2-x_1}</math>
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We are give the points <math>(m,3)</math> and <math>(1,m)</math>.
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Substituting into the slope formula, we get <math>\frac{m-3}{1-m}</math>
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After taking the cross-products and solving, we get <math>\text{(C) } \sqrt{3}\quad</math>.
  
 
== See also ==
 
== See also ==

Revision as of 16:48, 13 April 2016

Problem

If $m>0$ and the points $(m,3)$ and $(1,m)$ lie on a line with slope $m$, then $m=$

$\text{(A) } 1\quad \text{(B) } \sqrt{2}\quad \text{(C) } \sqrt{3}\quad \text{(D) } 2\quad \text{(E) } \sqrt{5}$

Solution

We know that the formula for slope is $m = \frac{y_2-y_1}{x_2-x_1}$ We are give the points $(m,3)$ and $(1,m)$. Substituting into the slope formula, we get $\frac{m-3}{1-m}$ After taking the cross-products and solving, we get $\text{(C) } \sqrt{3}\quad$.

See also

1992 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
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All AHSME Problems and Solutions

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