Difference between revisions of "2001 AIME I Problems/Problem 12"
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triple I = (2/3,2/3,2/3); | triple I = (2/3,2/3,2/3); | ||
triple J = (6/7,20/21,26/21); | triple J = (6/7,20/21,26/21); | ||
− | draw(C--A--D--C--B--D--B--A--C) | + | draw(C--A--D--C--B--D--B--A--C) |
draw(L--F--N--E--M--G--L--I--M--I--N--I--J); | draw(L--F--N--E--M--G--L--I--M--I--N--I--J); | ||
label("$I$",I,W); | label("$I$",I,W); |
Revision as of 21:23, 26 January 2015
Problem
A sphere is inscribed in the tetrahedron whose vertices are and The radius of the sphere is where and are relatively prime positive integers. Find
Solution
import three; pointpen = black; pathpen = black+linewidth(0.7); currentprojection = perspective(-2,9,4); triple A = (6,0,0), B = (0,4,0), C = (0,0,2), D = (0,0,0); triple E = (2/3,0,0), F = (0,2/3,0), G = (0,0,2/3), L = (0,2/3,2/3), M = (2/3,0,2/3), N = (2/3,2/3,0); triple I = (2/3,2/3,2/3); triple J = (6/7,20/21,26/21); draw(C--A--D--C--B--D--B--A--C) draw(L--F--N--E--M--G--L--I--M--I--N--I--J); label("$I$",I,W); label("$A$",A,S); label("$B$",B,S); label("$C$",C,W*-1); label("$D$",D,W*-1); (Error making remote request. Unknown error_msg)
The center of the insphere must be located at where is the sphere's radius. must also be a distance from the plane
The signed distance between a plane and a point can be calculated as , where G is any point on the plane, and P is a vector perpendicular to ABC.
A vector perpendicular to plane can be found as
Thus where the negative comes from the fact that we want to be in the opposite direction of
Finally
See also
- <url>viewtopic.php?p=384205#384205 Discussion on AoPS</url>
2001 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
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