Difference between revisions of "2013 AMC 8 Problems/Problem 5"
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==Solution== | ==Solution== | ||
| − | The median here is obviously less than the mean, so | + | The median here is obviously less than the mean, so options <math>(A)</math> and <math>(B)</math> are out. |
Lining up the numbers (5, 5, 6, 8, 106), we see that the median weight is 6 pounds. | Lining up the numbers (5, 5, 6, 8, 106), we see that the median weight is 6 pounds. | ||
Revision as of 00:10, 20 January 2015
Problem
Hammie is in the 
grade and weighs 106 pounds. His quadruplet sisters are tiny babies and weigh 5, 5, 6, and 8 pounds. Which is greater, the average (mean) weight of these five children or the median weight, and by how many pounds?
Solution
The median here is obviously less than the mean, so options 
and 
are out.
Lining up the numbers (5, 5, 6, 8, 106), we see that the median weight is 6 pounds.
The average weight of the five kids is 
.
Therefore, the average weight is bigger, by 
pounds, making the answer 
.
See Also
| 2013 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
