GET READY FOR THE AMC 12 WITH AoPS
Learn with outstanding instructors and top-scoring students from around the world in our AMC 12 Problem Series online course.
CHECK SCHEDULE

Difference between revisions of "2014 AMC 12B Problems"

(Problem 1)
(Problem 14)
Line 65: Line 65:
  
 
==Problem 14==
 
==Problem 14==
 +
Amy, Bob, Charlie, and Dorothy each select distinct integers between <math>1</math> and <math>10</math>, inclusive. What is the probability that the four integers are side lengths of a cyclic quadrilateral?
  
 +
<math>\textbf{(A)}\ 0 \qquad \textbf{(B)}\ \frac{1}{16} \qquad \textbf{(C)}\ \frac{1}{12} \qquad \textbf{(D)}\ \frac{1}{8} \qquad \textbf{(E)}\ \frac{1}{4}</math>
  
 
[[2014 AMC 12B Problems/Problem 14|Solution]]
 
[[2014 AMC 12B Problems/Problem 14|Solution]]

Revision as of 21:05, 8 February 2014

Problem 1

Solution

Problem 2

Solution

Problem 3

Solution

Problem 4

Solution

Problem 5

Solution

Problem 6

Solution

Problem 7

Solution

Problem 8

Solution

Problem 9

Solution

Problem 10

Solution

Problem 11

Solution

Problem 12

Solution

Problem 13

Solution

Problem 14

Amy, Bob, Charlie, and Dorothy each select distinct integers between $1$ and $10$, inclusive. What is the probability that the four integers are side lengths of a cyclic quadrilateral?

$\textbf{(A)}\ 0 \qquad \textbf{(B)}\ \frac{1}{16} \qquad \textbf{(C)}\ \frac{1}{12} \qquad \textbf{(D)}\ \frac{1}{8} \qquad \textbf{(E)}\ \frac{1}{4}$

Solution

Problem 15

Solution

Problem 16

Solution

Problem 17

Solution

Problem 18

Solution

Problem 19

Solution

Problem 20

Solution

Problem 21

Solution

Problem 22

Solution

Problem 23

Solution

Problem 24

Solution

Problem 25

Solution