Difference between revisions of "2014 AMC 12A Problems/Problem 7"
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<math>\sqrt 3</math>, <math>\sqrt[3]3</math>, and <math>\sqrt[6]3</math> which is equivalent to <math>3^{\frac{3}{6}}</math>, <math>3^{\frac{2}{6}}</math>, and <math>3^{\frac{1}{6}}</math> | <math>\sqrt 3</math>, <math>\sqrt[3]3</math>, and <math>\sqrt[6]3</math> which is equivalent to <math>3^{\frac{3}{6}}</math>, <math>3^{\frac{2}{6}}</math>, and <math>3^{\frac{1}{6}}</math> | ||
− | so the next term will be <math>3^{frac{0}{6}}</math> which is equal to <math>1\textbf{(A) }\qquad</math> | + | so the next term will be <math>3^{\frac{0}{6}}</math> which is equal to <math>1\textbf{(A) }\qquad</math> |
Revision as of 17:47, 7 February 2014
Problem 7
The first three terms of a geometric progression are , , and . What is the fourth term?
Solution
so the terms are
, , and which is equivalent to , , and so the next term will be which is equal to