Difference between revisions of "1988 AHSME Problems/Problem 1"
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So adding the two terms we get <math> 2 \sqrt{2} + 3 \sqrt{2} = 5 \sqrt{2} </math> , which corresponds to answer choice <math>\boxed{\textbf{(D)}}</math> . | So adding the two terms we get <math> 2 \sqrt{2} + 3 \sqrt{2} = 5 \sqrt{2} </math> , which corresponds to answer choice <math>\boxed{\textbf{(D)}}</math> . | ||
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| + | == See also == | ||
| + | {{AHSME box|year=1988|before=First Question|num-a=2}} | ||
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| + | [[Category: Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 00:42, 23 October 2014
Problem
![\[\text{(A)}\ \sqrt{20}\qquad\text{(B)}\ 2(\sqrt{2}+\sqrt{3})\qquad\text{(C)}\ 7\qquad\text{(D)}\ 5\sqrt{2}\qquad\text{(E)}\ 2\sqrt{13}\]](http://latex.artofproblemsolving.com/a/e/f/aef5c444783d6bda9508ab5bc9016312e5a99fab.png)
Solution
So adding the two terms we get 
, which corresponds to answer choice 
.
See also
| 1988 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
