Difference between revisions of "2013 AMC 8 Problems/Problem 24"
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draw(A--B); | draw(A--B); | ||
draw(C--B); | draw(C--B); | ||
− | draw(D--A); | + | draw(D--A); |
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draw(F--E); | draw(F--E); | ||
draw(I--J); | draw(I--J); | ||
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draw(A--J); | draw(A--J); | ||
filldraw(A--B--C--I--J--cycle,grey); | filldraw(A--B--C--I--J--cycle,grey); | ||
+ | draw(E--I); | ||
label("$A$", A, NW); | label("$A$", A, NW); | ||
label("$B$", B, NE); | label("$B$", B, NE); |
Revision as of 13:03, 27 November 2013
Problem
Squares , , and are equal in area. Points and are the midpoints of sides and , respectively. What is the ratio of the area of the shaded pentagon to the sum of the areas of the three squares?
Solution
See Also
2013 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.