Difference between revisions of "1950 AHSME Problems/Problem 36"
DarkPikachu (talk | contribs) m (→Problem) |
Rachanamadhu (talk | contribs) (→Solution) |
||
| Line 10: | Line 10: | ||
==Solution== | ==Solution== | ||
| − | Since there is a 20% off sale, then the new price is <math>0.8\cdot2.50</math>. | + | Since there is a 20% off sale, then the new price is <math>0.8\cdot2.50</math>. Albert buys five of them, so the amount saved is the price he had to pay with the 20% sale subtracted from the price he had to pay with no sale: |
<math>(5\cdot2.50)-(5\cdot0.8\cdot2.50)=(5\cdot2.50)-(4\cdot2.50)</math> | <math>(5\cdot2.50)-(5\cdot0.8\cdot2.50)=(5\cdot2.50)-(4\cdot2.50)</math> | ||
| Line 16: | Line 16: | ||
<math>=2.50</math> | <math>=2.50</math> | ||
<math>\text{Answer: }\boxed{\mathbf{(C)}}</math> | <math>\text{Answer: }\boxed{\mathbf{(C)}}</math> | ||
| − | |||
==See Also== | ==See Also== | ||
Revision as of 13:14, 19 April 2015
Problem
A merchant buys goods at 
off the list price. He desires to mark the goods so that he can give a discount of 
on the marked price and still clear a profit of on the selling price. What percent of the list price must he mark the goods?
Solution
Since there is a 20% off sale, then the new price is 
. Albert buys five of them, so the amount saved is the price he had to pay with the 20% sale subtracted from the price he had to pay with no sale:
See Also
| 1950 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 35 |
Followed by Problem 37 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
