Difference between revisions of "1985 AHSME Problems/Problem 21"
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==Problem== | ==Problem== | ||
− | How many integers <math> x </math> satisfy the equation <math> (x^2-x-1)^{x+2}=1 </math> | + | How many integers <math> x </math> satisfy the equation <math> (x^2-x-1)^{x+2}=1 </math>? |
<math> \mathrm{(A)\ } 2 \qquad \mathrm{(B) \ }3 \qquad \mathrm{(C) \ } 4 \qquad \mathrm{(D) \ } 5 \qquad \mathrm{(E) \ }\text{none of these} </math> | <math> \mathrm{(A)\ } 2 \qquad \mathrm{(B) \ }3 \qquad \mathrm{(C) \ } 4 \qquad \mathrm{(D) \ } 5 \qquad \mathrm{(E) \ }\text{none of these} </math> | ||
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<math> x=0, 1 </math> | <math> x=0, 1 </math> | ||
− | However, <math> x=1 </math> gives an odd power of <math> -1 </math>, so this is discarded. Finally, notice that anything to the <math> 0\text{th} </math> power (except for <math> 0 </math>, | + | However, <math> x=1 </math> gives an odd power of <math> -1 </math>, so this is discarded. Finally, notice that anything to the <math> 0\text{th} </math> power (except for <math> 0 </math>, as <math>0^0</math> is undefined) gives <math> 1 </math>. |
<math> x+2=0 </math> | <math> x+2=0 </math> |
Revision as of 00:04, 3 April 2018
Problem
How many integers satisfy the equation ?
Solution
Notice that any power of is , so would give valid solutions.
Also, to an even power also gives , so we check
However, gives an odd power of , so this is discarded. Finally, notice that anything to the power (except for , as is undefined) gives .
This doesn't make , so this is also valid.
Overall, our valid solutions are for a grand total of .
See Also
1985 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 20 |
Followed by Problem 22 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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