Difference between revisions of "1974 AHSME Problems/Problem 4"

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==Solution==
 
==Solution==
 
From the [[Remainder Theorem]], the remainder when <math> x^{51}+51 </math> is divided by <math> x+1 </math> is <math> (-1)^{51}+51=-1+51=50, \boxed{\text{D}} </math>.
 
From the [[Remainder Theorem]], the remainder when <math> x^{51}+51 </math> is divided by <math> x+1 </math> is <math> (-1)^{51}+51=-1+51=50, \boxed{\text{D}} </math>.
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== Video Solution by OmegaLearn ==
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https://youtu.be/Dp-pw6NNKRo?t=256
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~ pi_is_3.14
  
 
==See Also==
 
==See Also==

Revision as of 06:41, 4 November 2022

Problem

What is the remainder when $x^{51}+51$ is divided by $x+1$?

$\mathrm{(A)\ } 0 \qquad \mathrm{(B) \ }1 \qquad \mathrm{(C) \  } 49 \qquad \mathrm{(D) \  } 50 \qquad \mathrm{(E) \  }51$

Solution

From the Remainder Theorem, the remainder when $x^{51}+51$ is divided by $x+1$ is $(-1)^{51}+51=-1+51=50, \boxed{\text{D}}$.

Video Solution by OmegaLearn

https://youtu.be/Dp-pw6NNKRo?t=256

~ pi_is_3.14

See Also

1974 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
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