Difference between revisions of "2009 AMC 10A Problems/Problem 1"

Revision as of 18:04, 30 August 2017

One can hold $12$ ounces of soda. What is the minimum number of cans needed to provide a gallon ( $128$ ounces) of soda?

$\mathrm{(A)}\ 7\qquad \mathrm{(B)}\ 8\qquad \mathrm{(C)}\ 9\qquad \mathrm{(D)}\ 10\qquad \mathrm{(E)}\ 11$

$10$ cans would hold $120$ ounces, but $128>120$ , so $11$ cans are required. Thus, the answer is $\mathrm{(E)}$ .

2009 AMC 10A (Problems • Answer Key • Resources)
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All AMC 10 Problems and Solutions

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 == Problem ==
-One can holds <math>12</math> ounces of soda. What is the minimum number of cans needed to provide a gallon (<math>128</math> ounces) of soda?
+One can hold <math>12</math> ounces of soda. What is the minimum number of cans needed to provide a gallon (<math>128</math> ounces) of soda?
 <math>\mathrm{(A)}\ 7\qquad