Difference between revisions of "1982 USAMO Problems/Problem 3"
(Created page with "== Problem == If a point <math>A_1</math> is in the interior of an equilateral triangle <math>ABC</math> and point <math>A_2</math> is in the interior of <math>\triangle{A_1BC}</...") |
|||
| Line 13: | Line 13: | ||
== See Also == | == See Also == | ||
{{USAMO box|year=1982|num-b=2|num-a=4}} | {{USAMO box|year=1982|num-b=2|num-a=4}} | ||
| + | {{MAA Notice}} | ||
[[Category:Olympiad Geometry Problems]] | [[Category:Olympiad Geometry Problems]] | ||
Revision as of 18:13, 3 July 2013
Problem
If a point 
is in the interior of an equilateral triangle 
and point 
is in the interior of 
, prove that
,
where the isoperimetric quotient of a figure 
is defined by
![$I.Q.(F) = \frac{\text{Area (F)}}{\text{[Perimeter (F)]}^2}$](http://latex.artofproblemsolving.com/5/9/6/59605bef5fa499b868bb9d25da48807658139b0a.png)
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See Also
| 1982 USAMO (Problems • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 | ||
| All USAMO Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
