Difference between revisions of "2013 AMC 10B Problems/Problem 1"
Countingkg (talk | contribs) (Created page with "==Problem== What is <math>\frac{2+4+6}{1+3+5} - \frac{1+3+5}{2+4+6}</math>? <math> \textbf{(A)}\ -1 \qquad\textbf{(B)}\ \frac{5}{36} \qquad\textbf{(C)}\ \frac{7}{12} \qquad\te...") |
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This expression is equivalent to <math>\frac{12}{9} - \frac{9}{12} = \frac{16}{12} - \frac{9}{12} = \boxed{\textbf{(C) }\frac{7}{12}}</math> | This expression is equivalent to <math>\frac{12}{9} - \frac{9}{12} = \frac{16}{12} - \frac{9}{12} = \boxed{\textbf{(C) }\frac{7}{12}}</math> | ||
| + | ==See Also== | ||
| + | |||
| + | {{AMC10 box|year=2013|ab=B|before=First Problem|num-a=2}} | ||
Revision as of 15:56, 27 March 2013
Problem
What is 
?
Solution
This expression is equivalent to 
See Also
| 2013 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
