Difference between revisions of "2013 AMC 12A Problems/Problem 4"

Revision as of 21:33, 6 February 2013

$\frac{2^{2014}+2^{2012}}{2^{2014}-2^{2012}}$

We can factor a ${2^{2012}}$ out of the numerator and denominator to obtain

$\frac{2^{2012}*(2^2+1)}{2^{2012}*(2^2-1)}$

Both the ${2^{2012}}$ terms cancel, so we get

$\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}$ , which is C

@@ Line 1: / Line 1: @@
 <math>\frac{2^{2014}+2^{2012}}{2^{2014}-2^{2012}}</math>
-We can factor a 2^2012 out of the numerator and denominator to obtain
+We can factor a <math>{2^{2012}}</math> out of the numerator and denominator to obtain
 <math>\frac{2^{2012}*(2^2+1)}{2^{2012}*(2^2-1)}</math>
-Both the (2^2012) terms cancel, so we get
+Both the <math>{2^{2012}}</math> terms cancel, so we get
 <math>\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}</math>, which is C