Difference between revisions of "1995 AJHSME Problems/Problem 18"

Revision as of 13:03, 19 October 2016

Problem

The area of each of the four congruent L-shaped regions of this 100-inch by 100-inch square is 3/16 of the total area. How many inches long is the side of the center square?

$[asy] draw((20,2)--(2,-2)--(-2,-2)--(-2,2)--cycle); draw((1,1)--(1,-1)--(-1,-1)--(-1,1)--cycle); draw((0,1)--(0,2)); draw((1,0)--(2,0)); draw((0,-1)--(0,-2)); draw((-1,0)--(-2,0)); [/asy]$

$\text{(A)}\ 25 \qquad \text{(B)}\ 44 \qquad \text{(C)}\ 50 \qquad \text{(D)}\ 62 \qquad \text{(E)}\ 75$

Solution

The area taken up by the L's is $4*\frac{3}{16}=\frac{3}{4}$ of the area of the whole square. What remains has $\frac{1}{4}$ of the area of the larger square. $\frac{100*100}{4}=\frac{100}{2}*\frac{100}{2}=50*50$ is the area of the smaller square, so its side length is 50. $\text{(C)}$

1995 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 17	Followed by Problem 19
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Difference between revisions of "1995 AJHSME Problems/Problem 18"

Revision as of 13:03, 19 October 2016

Problem

Solution

See Also

@@ Line 4: / Line 4: @@
 <asy>
-draw((2,2)--(2,-2)--(-2,-2)--(-2,2)--cycle);
+draw((20,2)--(2,-2)--(-2,-2)--(-2,2)--cycle);
 draw((1,1)--(1,-1)--(-1,-1)--(-1,1)--cycle);
 draw((0,1)--(0,2));