Difference between revisions of "1994 AJHSME Problems/Problem 14"
| Line 10: | Line 10: | ||
==See Also== | ==See Also== | ||
{{AJHSME box|year=1994|num-b=13|num-a=15}} | {{AJHSME box|year=1994|num-b=13|num-a=15}} | ||
| + | {{MAA Notice}} | ||
Revision as of 23:13, 4 July 2013
Problem
Two children at a time can play pairball. For 
minutes, with only two children playing at time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is
Solution
There are 
minutes of total playing time. Divided equally among the five children, each child gets 
minutes.
See Also
| 1994 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
