Difference between revisions of "2012 AMC 8 Problems/Problem 12"
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<math> \textbf{(A)}\hspace{.05in}1\qquad\textbf{(B)}\hspace{.05in}3\qquad\textbf{(C)}\hspace{.05in}5\qquad\textbf{(D)}\hspace{.05in}7\qquad\textbf{(E)}\hspace{.05in}9 </math> | <math> \textbf{(A)}\hspace{.05in}1\qquad\textbf{(B)}\hspace{.05in}3\qquad\textbf{(C)}\hspace{.05in}5\qquad\textbf{(D)}\hspace{.05in}7\qquad\textbf{(E)}\hspace{.05in}9 </math> | ||
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+ | ==Solution== | ||
+ | The problem wants us to find the units digit of <math> 13^{2012} </math>, therefore, we can eliminate the tens digit of <math> 13 </math>, because the tens digit will not affect the final result. So our new expression is <math> 3^{2012} </math>. Now we need to look for a pattern in the units digit. | ||
+ | |||
+ | <math> 3^1 \implies 3 </math> | ||
+ | |||
+ | <math> 3^2 \implies 9 </math> | ||
+ | |||
+ | <math> 3^3 \implies 7 </math> | ||
+ | |||
+ | <math> 3^4 \implies 1 </math> | ||
+ | |||
+ | <math> 3^5 \implies 3 </math> | ||
+ | |||
+ | We observe that there is a pattern for the units digit which recurs every four powers of three. Using this pattern, we find that the units digit of <math> 13^{2012} </math> is | ||
+ | <math> \boxed{{\textbf{(A)}\ 1}} </math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2012|num-b=11|num-a=13}} | {{AMC8 box|year=2012|num-b=11|num-a=13}} |
Revision as of 10:50, 24 November 2012
What is the units digit of ?
Solution
The problem wants us to find the units digit of , therefore, we can eliminate the tens digit of , because the tens digit will not affect the final result. So our new expression is . Now we need to look for a pattern in the units digit.
We observe that there is a pattern for the units digit which recurs every four powers of three. Using this pattern, we find that the units digit of is .
See Also
2012 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |