Difference between revisions of "2011 AMC 8 Problems/Problem 2"

Revision as of 00:58, 5 July 2013

Problem

Karl's rectangular vegetable garden is $20$ feet by $45$ feet, and Makenna's is $25$ feet by $40$ feet. Whose garden is larger in area?

$\textbf{(A)}\ \text{Karl's garden is larger by 100 square feet.}$

$\textbf{(B)}\ \text{Karl's garden is larger by 25 square feet.}$

$\textbf{(C)}\ \text{The gardens are the same size.}$

$\textbf{(D)}\ \text{Makenna's garden is larger by 25 square feet.}$

$\textbf{(E)}\ \text{Makenna's garden is larger by 100 square feet.}$

Solution

The area of a rectangle is given by the formula length times width. Karl's garden is $20 \times 45 = 900$ square feet and Makenna's garden is $25 \times 40 = 1000$ square feet. Since $1000 > 900,$ Makenna's garden is larger by $1000-900=100$ square feet. $\Rightarrow \boxed{ \textbf{(E)}\ \text{Makenna's garden is larger by 100 square feet.} }$

2011 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 ==See Also==
 {{AMC8 box|year=2011|num-b=1|num-a=3}}
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Difference between revisions of "2011 AMC 8 Problems/Problem 2"

Revision as of 00:58, 5 July 2013

Problem

Solution

See Also