Difference between revisions of "Triangle Inequality"

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<math>\displaystyle AC + AB > BC</math>
 
<math>\displaystyle AC + AB > BC</math>
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This inequality often shows up in contest problems.
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== See Also ==
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*[[Algebra]]
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*[[Inequality]]
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*[[Geometric inequalities]]
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*[[Triangle]]
  
 
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Revision as of 00:14, 7 July 2006

In a nondegenerate triangle $\displaystyle ABC$:

$\displaystyle AB + BC > AC$

$\displaystyle BC + AC > AB$

$\displaystyle AC + AB > BC$

This inequality often shows up in contest problems.

See Also

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