Difference between revisions of "2012 AMC 10A Problems/Problem 11"
(→Solution) |
|||
Line 40: | Line 40: | ||
{{AMC10 box|year=2012|ab=A|num-b=10|num-a=12}} | {{AMC10 box|year=2012|ab=A|num-b=10|num-a=12}} | ||
+ | {{MAA Notice}} |
Revision as of 11:04, 4 July 2013
Problem
Externally tangent circles with centers at points A and B have radii of lengths 5 and 3, respectively. A line externally tangent to both circles intersects ray AB at point C. What is BC?
Solution
Let and be the points of tangency on circles and with line . . Also, let . As and are right angles (a radius is perpendicular to a tangent line at the point of tangency) and both triangles share , . From this we can get a proportion.
See Also
2012 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.