Difference between revisions of "2012 AMC 10A Problems/Problem 2"
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<math> \textbf{(A)}\ \emph{2\ by\ 4}\qquad\textbf{(B)}\ \emph{\ 2\ by\ 6}\qquad\textbf{(C)}\ \emph{\ 2\ by\ 8}\qquad\textbf{(D)}\ \emph{4\ by\ 4}\qquad\textbf{(E)}\ \emph{4\ by\ 8} </math> | <math> \textbf{(A)}\ \emph{2\ by\ 4}\qquad\textbf{(B)}\ \emph{\ 2\ by\ 6}\qquad\textbf{(C)}\ \emph{\ 2\ by\ 8}\qquad\textbf{(D)}\ \emph{4\ by\ 4}\qquad\textbf{(E)}\ \emph{4\ by\ 8} </math> | ||
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| + | == Solution == | ||
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| + | Cutting the square in half will bisect one pair of sides while the other side will remain unchanged. Thus, the new square is <math>\frac{8}{2}*8 = \qquad\textbf{(E)}\ 4*8</math>. | ||
Revision as of 18:33, 8 February 2012
Problem 2
A square with side length 8 is cut in half, creating two congruent rectangles. What are the dimensions of one of these rectangles?
Solution
Cutting the square in half will bisect one pair of sides while the other side will remain unchanged. Thus, the new square is 
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