Difference between revisions of "1950 AHSME Problems/Problem 29"

(Created page with "==Problem== A manufacturer built a machine which will address <math>500</math> envelopes in <math>8</math> minutes. He wishes to build another machine so that when both are oper...")
 
(solution & see also sections)
Line 1: Line 1:
 
==Problem==
 
==Problem==
 
 
A manufacturer built a machine which will address <math>500</math> envelopes in <math>8</math> minutes. He wishes to build another machine so that when both are operating together they will address <math>500</math> envelopes in <math>2</math> minutes. The equation used to find how many minutes <math>x</math> it would require the second machine to address <math>500</math> envelopes alone is:
 
A manufacturer built a machine which will address <math>500</math> envelopes in <math>8</math> minutes. He wishes to build another machine so that when both are operating together they will address <math>500</math> envelopes in <math>2</math> minutes. The equation used to find how many minutes <math>x</math> it would require the second machine to address <math>500</math> envelopes alone is:
  
Line 8: Line 7:
 
\textbf{(D)}\ \dfrac{x}{2}+\dfrac{x}{8}=1 \qquad\\
 
\textbf{(D)}\ \dfrac{x}{2}+\dfrac{x}{8}=1 \qquad\\
 
\textbf{(E)}\ \text{None of these answers}</math>
 
\textbf{(E)}\ \text{None of these answers}</math>
 +
 +
==Solution==
 +
{{solution}}
 +
 +
==See Also==
 +
{{AHSME box|year=1950|num-b=28|num-a=30}}
 +
 +
[[Category:Introductory Algebra Problems]]

Revision as of 13:20, 17 April 2012

Problem

A manufacturer built a machine which will address $500$ envelopes in $8$ minutes. He wishes to build another machine so that when both are operating together they will address $500$ envelopes in $2$ minutes. The equation used to find how many minutes $x$ it would require the second machine to address $500$ envelopes alone is:

$\textbf{(A)}\ 8-x=2 \qquad \textbf{(B)}\ \dfrac{1}{8}+\dfrac{1}{x}=\dfrac{1}{2} \qquad \textbf{(C)}\ \dfrac{500}{8}+\dfrac{500}{x}=500 \qquad \textbf{(D)}\ \dfrac{x}{2}+\dfrac{x}{8}=1 \qquad\\ \textbf{(E)}\ \text{None of these answers}$

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See Also

1950 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 28
Followed by
Problem 30
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions