Difference between revisions of "2008 iTest Problems/Problem 9"

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== Problem ==
 
== Problem ==
  
(story eliminated)
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Joshua likes to play with numbers and patterns. Joshua's favorite number is <math>6</math> because it is the units digit of his birth year, <math>1996</math>.
 
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Part of the reason Joshua likes the number 6 so much is that the powers of <math>6</math> all have the same units digit as they grow from <math>6^1</math>:
What is the units digit of <math>2008^{2008}</math>?
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<cmath>\begin{align*}6^1&=6,\\6^2&=36,\\6^3&=216,\\6^4&=1296,\\6^5&=7776,\\6^6&=46656,\\\vdots\end{align*}</cmath>
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However, not all units digits remain constant when exponentiated in this way. One day Joshua asks Michael if there are
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simple patterns for the units digits when each one-digit integer is exponentiated in the manner above. Michael responds,
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"You tell me!" Joshua gives a disappointed look, but then Michael suggests that Joshua play around with some numbers
 +
and see what he can discover. "See if you can find the units digit of <math>2008^{2008}</math>," Michael challenges. After a little while,
 +
Joshua finds an answer which Michael confirms is correct. What is Joshua's correct answer (the units digit of <math>2008^{2008}</math>)?  
  
 
== Solution ==
 
== Solution ==
 
The statement is equivalent to <math>2008^{2008}\pmod {10}</math>. We can simplify this to <math>8^{2008} \pmod {10}</math>. We see that <math>8^1 \equiv 8 \pmod {10}</math>, <math>8^2 \equiv 4 \pmod {10}</math>, <math>8^3 \equiv 2 \pmod {10}</math>, <math>8^4 \equiv 6 \pmod {10}</math>, and <math>8^5 \equiv 8 \pmod {10}</math>. We see that this pattern will repeat every <math>4</math> terms. Thus, because <math>8^4 \equiv 6 \pmod {10}</math> and the pattern repeats every <math>4</math> terms, <math>8^{2008}\equiv \boxed{6} \pmod {10}</math>.
 
The statement is equivalent to <math>2008^{2008}\pmod {10}</math>. We can simplify this to <math>8^{2008} \pmod {10}</math>. We see that <math>8^1 \equiv 8 \pmod {10}</math>, <math>8^2 \equiv 4 \pmod {10}</math>, <math>8^3 \equiv 2 \pmod {10}</math>, <math>8^4 \equiv 6 \pmod {10}</math>, and <math>8^5 \equiv 8 \pmod {10}</math>. We see that this pattern will repeat every <math>4</math> terms. Thus, because <math>8^4 \equiv 6 \pmod {10}</math> and the pattern repeats every <math>4</math> terms, <math>8^{2008}\equiv \boxed{6} \pmod {10}</math>.
  
== See also ==
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== See Also ==
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{{2008 iTest box|num-b=7|num-a=9}}
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[[Category:Introductory Number Theory Problems]]
 
[[Category:Introductory Number Theory Problems]]

Revision as of 00:02, 22 June 2018

Problem

Joshua likes to play with numbers and patterns. Joshua's favorite number is $6$ because it is the units digit of his birth year, $1996$. Part of the reason Joshua likes the number 6 so much is that the powers of $6$ all have the same units digit as they grow from $6^1$: \begin{align*}6^1&=6,\\6^2&=36,\\6^3&=216,\\6^4&=1296,\\6^5&=7776,\\6^6&=46656,\\\vdots\end{align*} However, not all units digits remain constant when exponentiated in this way. One day Joshua asks Michael if there are simple patterns for the units digits when each one-digit integer is exponentiated in the manner above. Michael responds, "You tell me!" Joshua gives a disappointed look, but then Michael suggests that Joshua play around with some numbers and see what he can discover. "See if you can find the units digit of $2008^{2008}$," Michael challenges. After a little while, Joshua finds an answer which Michael confirms is correct. What is Joshua's correct answer (the units digit of $2008^{2008}$)?

Solution

The statement is equivalent to $2008^{2008}\pmod {10}$. We can simplify this to $8^{2008} \pmod {10}$. We see that $8^1 \equiv 8 \pmod {10}$, $8^2 \equiv 4 \pmod {10}$, $8^3 \equiv 2 \pmod {10}$, $8^4 \equiv 6 \pmod {10}$, and $8^5 \equiv 8 \pmod {10}$. We see that this pattern will repeat every $4$ terms. Thus, because $8^4 \equiv 6 \pmod {10}$ and the pattern repeats every $4$ terms, $8^{2008}\equiv \boxed{6} \pmod {10}$.

See Also

2008 iTest (Problems)
Preceded by:
Problem 7
Followed by:
Problem 9
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