Difference between revisions of "1950 AHSME Problems/Problem 4"
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Revision as of 13:29, 17 April 2012
Problem
Reduced to lowest terms, 
is equal to:
Solution
We start off by simplifying the second term.
![\[-\frac{ab-b^2}{ab-a^2} = -\frac{b(a-b)}{-a(a-b)} = \frac{b}{a}.\]](http://latex.artofproblemsolving.com/b/d/a/bda210f1dcc7a20cc65ea176cc7eee74d817bf06.png)
Now create a common denominator and simplify.
![\[\frac{a^2-b^2}{ab}+\frac{b}{a}=\frac{a^2-b^2}{ab}+\frac{b^2}{ab} = \frac{a^2}{ab} = \boxed{\mathrm{(A) }\frac{a}{b}}\]](http://latex.artofproblemsolving.com/3/0/d/30de8e5e5a71aca066b9c9ffbbbabcae654da1c2.png)
See Also
| 1950 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
