Difference between revisions of "1998 AJHSME Problems/Problem 14"
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==Solution== | ==Solution== | ||
| − | If <math>80\%</math> of the people in the science club of <math>15</math> people are in the Math Club, <math>\frac{4}{5}\times15=12</math> people are in the Math Club | + | If <math>80\%</math> of the people in the science club of <math>15</math> people are in the Math Club, <math>\frac{4}{5}\times15=12</math> people are in the both the Math Club and the Science Club. |
| − | <math>12</math> | + | These <math>12</math> people are also <math>30\%</math> of the Math Club. |
| − | + | Setting up a proportion: | |
| − | <math> | + | <math>\frac{12}{30\%} = \frac{x}{100\%}</math> |
| − | <math>40= | + | <math>12\cdot 1.00 =0.30\cdot x</math> |
| + | |||
| + | <math>\frac{12}{0.3} = 40=x </math> | ||
There are <math>40=\boxed{E}</math> people in the Math Club. | There are <math>40=\boxed{E}</math> people in the Math Club. | ||
| − | |||
== See also == | == See also == | ||
Revision as of 10:33, 31 July 2011
Problem 14
An Annville Junior High School, 
of the students in the Math Club are in the Science Club, and 
of the students in the Science Club are in the Math Club. There are 15 students in the Science Club. How many students are in the Math Club?
Solution
If of the people in the science club of 
people are in the Math Club, 
people are in the both the Math Club and the Science Club.
These 
people are also of the Math Club.
Setting up a proportion:
There are 
people in the Math Club.
See also
| 1998 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
