Difference between revisions of "2007 AMC 10B Problems/Problem 15"
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Latest revision as of 11:22, 4 July 2013
- The following problem is from both the 2007 AMC 12B #11 and 2007 AMC 10B #15, so both problems redirect to this page.
Problem
The angles of quadrilateral 
satisfy 
What is the degree measure of 
rounded to the nearest whole number?
Solution
The sum of the interior angles of any quadrilateral is 
![\[\angle A = 360 \cdot \frac{12}{25} = 172.8 \approx \boxed{\mathrm{(D) \ } 173}\]](http://latex.artofproblemsolving.com/2/8/8/288a357b357408d940cbe49d2de74f1f15a2fc78.png)
See Also
| 2007 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 10 |
Followed by Problem 12 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
| 2007 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 14 |
Followed by Problem 16 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
