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Revision as of 20:39, 3 June 2011


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There have been 237,031 edits to 10,609 articles since January, 2006.

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Problem of the Day

Solve for $x$. $x+12=15$. Bob and Janna blah blah blah go to the store. Let me copy another problem... Let $x_1, x_2, ... , x_6$ be non-negative real numbers such that $x_1 +x_2 +x_3 +x_4 +x_5 +x_6 =1$, and $x_1 x_3 x_5 +x_2 x_4 x_6 \ge {\scriptstyle\frac{1}{540}}$. Let $p$ and $q$ be positive relatively prime integers such that $\frac{p}{q}$ is the maximum possible value of $x_1 x_2 x_3 + x_2 x_3 x_4 +x_3 x_4 x_5 +x_4 x_5 x_6 +x_5 x_6 x_1 +x_6 x_1 x_2$. Find $p+q$.

(View Answer/Add Solution)

Welcome to the AoPSWiki! The AoPSWiki is a wiki (or a publicly editable online resource) project administered by the Art of Problem Solving for supporting educational content useful to avid math students. Unlike most online resources, the AoPSWiki is meant to be easily readable by even the least advanced student. Also, the AoPSWiki, being a wiki, can be edited by anyone!

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