Difference between revisions of "2001 AMC 8 Problems/Problem 3"
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==Solution== | ==Solution== | ||
| − | Since Anjou has <math> \frac{1}{3} </math> the amount of money as Granny Smith and Granny Smith has <math> | + | Since Anjou has <math> \frac{1}{3} </math> the amount of money as Granny Smith and Granny Smith has $<math> 63</math>, Anjou has <math> \frac{1}{3}\times63=21 </math> dollars. Elberta has $<math> 2</math> more than this, so she has $<math> 23 </math>, or <math>\boxed{\text{E}} </math>. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2001|num-b=2|num-a=4}} | {{AMC8 box|year=2001|num-b=2|num-a=4}} | ||
Revision as of 23:28, 30 July 2011
Problem
Granny Smith has <dollar/>63. Elberta has <dollar/>2 more than Anjou and Anjou has one-third as much as Granny Smith. How many dollars does Elberta have?
Solution
Since Anjou has 
the amount of money as Granny Smith and Granny Smith has $
, Anjou has 
dollars. Elberta has $
more than this, so she has $
, or 
.
See Also
| 2001 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
