Difference between revisions of "2001 AMC 12 Problems/Problem 20"
Megamudkipz (talk | contribs) (add diagram) |
(→See Also) |
||
| Line 35: | Line 35: | ||
{{AMC12 box|year=2001|num-b=19|num-a=21}} | {{AMC12 box|year=2001|num-b=19|num-a=21}} | ||
| + | {{MAA Notice}} | ||
Revision as of 20:04, 3 July 2013
Problem
Points 
, 
, 
, and 
lie in the first quadrant and are the vertices of quadrilateral 
. The quadrilateral formed by joining the midpoints of 
, 
, 
, and 
is a square. What is the sum of the coordinates of point 
?
Solution
![[asy] pair A=(3,9), B=(1,1), C=(5,3), D=(7,3); draw(A--B--C--D--cycle); label("$A$",A,N); label("$B$",B,SW); label("$C$",C,N); label("$D$",D,E); pair AB = (A + B)/2, BC = (B + C)/2, CD = (C + D)/2, DA = (D + A)/2; draw(AB--BC--CD--DA--cycle); [/asy]](http://latex.artofproblemsolving.com/8/c/f/8cfb9d6da99381de67ea5f718469d0ecfdf8c71c.png)
We already know two vertices of the square: 
and 
.
There are only two possibilities for the other vertices of the square: either they are 
and 
, or they are 
and 
. The second case would give us outside the first quadrant, hence the first case is the correct one. As is the midpoint of 
, we can compute 
, and 
.
See Also
| 2001 AMC 12 (Problems • Answer Key • Resources) | |
| Preceded by Problem 19 |
Followed by Problem 21 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
