Difference between revisions of "2004 AMC 10B Problems/Problem 24"
Wanahakalugi (talk | contribs) m (→Solution) |
|||
| Line 6: | Line 6: | ||
== Solution == | == Solution == | ||
| − | Set <math>\segment BD</math>'s length as <math>x</math>. <math>CD</math>'s length must also be <math>x</math> since <math> \angle BAD </math> and <math> \angle DAC </math> intercept arcs of equal length. Using [[Ptolemy's Theorem]], <math>7x+8x=9(AD)</math>. The ratio is <math>\boxed{\frac{5}{3}}\implies( | + | Set <math>\segment BD</math>'s length as <math>x</math>. <math>CD</math>'s length must also be <math>x</math> since <math> \angle BAD </math> and <math> \angle DAC </math> intercept arcs of equal length. Using [[Ptolemy's Theorem]], <math>7x+8x=9(AD)</math>. The ratio is <math>\boxed{\frac{5}{3}}\implies(B)</math> |
| − | |||
== See Also == | == See Also == | ||
{{AMC10 box|year=2004|ab=B|num-b=23|num-a=25}} | {{AMC10 box|year=2004|ab=B|num-b=23|num-a=25}} | ||
Revision as of 22:34, 16 January 2012
In triangle 
we have 
, 
, 
. Point 
is on the circumscribed circle of the triangle so that 
bisects angle 
. What is the value of 
?
Solution
Set $\segment BD$ (Error compiling LaTeX. Unknown error_msg)'s length as 
. 
's length must also be since 
and 
intercept arcs of equal length. Using Ptolemy's Theorem, 
. The ratio is 
See Also
| 2004 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
