Difference between revisions of "2010 AMC 10B Problems/Problem 8"
| Line 1: | Line 1: | ||
We see how many common integer factors 48 and 64 share. | We see how many common integer factors 48 and 64 share. | ||
Of the factors of 48 - 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48; only 1, 2, 4, 8, and 16 are factors of 64. | Of the factors of 48 - 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48; only 1, 2, 4, 8, and 16 are factors of 64. | ||
| − | So there are <math>\boxed{(E) | + | So there are <math>\boxed{(E)5}</math> possibilities for the ticket price. |
Revision as of 13:50, 24 January 2011
We see how many common integer factors 48 and 64 share.
Of the factors of 48 - 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48; only 1, 2, 4, 8, and 16 are factors of 64.
So there are 
possibilities for the ticket price.
