Difference between revisions of "2010 AMC 10B Problems/Problem 2"
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The total time spent in meetings is <math>45 \text{ min} + 2*45\text{ min} = 2\text{ hours } 15 \text{ min} = 9/4 \text{ hours}</math> | The total time spent in meetings is <math>45 \text{ min} + 2*45\text{ min} = 2\text{ hours } 15 \text{ min} = 9/4 \text{ hours}</math> | ||
| − | Therefore, the percentage is < | + | Therefore, the percentage is <math></math>\frac{9/4 \text{ hours} }{9 \text{ hours}} = \frac{1}{4} = 25 \% = {(C)} 25}$ |
Revision as of 19:11, 22 January 2011
Problem
Makarla attended two meetings during her 
-hour work day. The first meeting took 
minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?
Solution
The percentage of her time spent in meetings is the total amount of time spent in meetings divided by the length of her workday.
The total time spent in meetings is 
Therefore, the percentage is $$ (Error compiling LaTeX. Unknown error_msg)\frac{9/4 \text{ hours} }{9 \text{ hours}} = \frac{1}{4} = 25 \% = {(C)} 25}$
