Difference between revisions of "2002 AMC 12A Problems/Problem 25"

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==Solution==
 
==Solution==
  
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'''(B)''' The sum of the coefficients of <math>P</math> and of <math>Q</math> will be equal, so <math>P(1) = Q(1)</math>. The only answer choice with an intersection at <math>x = 1</math> is at '''(B)'''. (The polynomials in the graph are <math>P(x) = 2x^4-3x^2-3x-4</math> and <math>Q(x) = -2x^4-2x^2-2x-2</math>.)
  
 
==See Also==
 
==See Also==
  
 
{{AMC12 box|year=2002|ab=A|num-b=24|after=Last<br>Problem}}
 
{{AMC12 box|year=2002|ab=A|num-b=24|after=Last<br>Problem}}

Revision as of 19:27, 26 January 2011

Problem

The nonzero coefficients of a polynomial $P$ with real coefficients are all replaced by their mean to form a polynomial $Q$. Which of the following could be a graph of $y = P(x)$ and $y = Q(x)$ over the interval $-4\leq x \leq 4$?

Solution

(B) The sum of the coefficients of $P$ and of $Q$ will be equal, so $P(1) = Q(1)$. The only answer choice with an intersection at $x = 1$ is at (B). (The polynomials in the graph are $P(x) = 2x^4-3x^2-3x-4$ and $Q(x) = -2x^4-2x^2-2x-2$.)

See Also

2002 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 24
Followed by
Last
Problem
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All AMC 12 Problems and Solutions