Difference between revisions of "1988 AJHSME Problems/Problem 10"

(New page: ==Problem== Chris' birthday is on a Thursday this year. What day of the week will it be <math>60</math> days after her birthday? <math>\text{(A)}\ \text{Monday} \qquad \text{(B)}\ \text...)
 
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==Solution==
 
==Solution==
7 days after her birthday would be a Thursday, as would 14, 21, 28, 35, 42, 49, and 56. Therefore the 60th would be four days after a Thursday, which is a <math>Monday\Rightarrow \mathrm{(A)}</math>.
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7 days after her birthday would be a Thursday, as would 14, 21, 28, 35, 42, 49, and 56. Therefore the 60th would be four days after a Thursday, which is a <math>\text{Monday} \Rightarrow \mathrm{(A)}</math>.
  
 
==See Also==
 
==See Also==
  
[[1988 AJHSME Problems]]
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{{AJHSME box|year=1988|num-b=9|num-a=11}}
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[[Category:Introductory Number Theory Problems]]

Revision as of 16:50, 2 June 2009

Problem

Chris' birthday is on a Thursday this year. What day of the week will it be $60$ days after her birthday?

$\text{(A)}\ \text{Monday} \qquad \text{(B)}\ \text{Wednesday} \qquad \text{(C)}\ \text{Thursday} \qquad \text{(D)}\ \text{Friday} \qquad \text{(E)}\ \text{Saturday}$

Solution

7 days after her birthday would be a Thursday, as would 14, 21, 28, 35, 42, 49, and 56. Therefore the 60th would be four days after a Thursday, which is a $\text{Monday} \Rightarrow \mathrm{(A)}$.

See Also

1988 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions